题目
此题为判断题(对,错)。
第1题
A.gap
B.break
C.globe
D.equality
第2题
The residents blame the police for the ____ in community relations.
A、breakthrough
B、breakaway
C、breakdown
D、break-up
第4题
145 Selective perception is _____ of new conflicting information that may result, in a breakdown in communication.
A. Encoding
B. Blocking out
C. Transmission
D. Acceptance
E. Decoding
第5题
The reason why the bread advertisement is misleading is that______.
A. thin slices of bread could contain more calories
B. the loaf was cut into regular slices
C. the bread was not genuine bread
D. the total number of calories in the loaf remained the same
第6题
What does the room rate include? 查看材料
A.Tax and breakfast.
B.Tax and service charge.
C.Service charge and breakfast.
D.Tax.
第7题
A.inti=100;while(i>0){i=i%100+1;Console.WriteLine(i);if(i>100)brea k;}
B.for(;;)
C.intk=1000;do{++k;Console.WriteLine(k);}while(k>=1000);
D.ints=36;while(s>=0){--s;Console.WriteLine(s);}
第8题
已知:int a,b;下列switch语句中,()是正确的。
A.switdh(a) { case a: a++;break; case b: b++:break: }
B.switch(a+b) { case 1:a+b; break; case 1:a-b }
C.switch(a*a) { case1,2:++a; case3,4:++b; }
D.swish(a/l0+b) { cases 5:a/5;break; default:a+b: }
第9题
执行语句序列 int n: cin>>n: switch (n) { case 1: case 2:cout<<'1'; case 3: case 4: cout<<'2': break; default: cout<<'3': }时,若键盘输入1,则屏幕显示
A.1
B.2
C.3
D.12
第10题
下列各程序段中,不是死循环的是()。
A.int j=100;
B.for(;;) while(1) {j=j%100+1; if(j>1000) break; }
C.int n=0;
D.int m=36; do{ while(m)--m; ++n; }while(n>=0);
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