与p∧﹁q相矛盾的蕴涵式是﹁p→q。

A.*p=*q

B.p=q

C.*p=&n1

D.p=*q

A.*p=*q;

B.p=q;

C.*p=&n1;

D.p=*q;

A.表达式错误

B.p与q之间数据个数

C.p占据的字节数

D.p与q之间的字节数

A.q->prior = p；p-> next=q；p -> next -> prior =q； q ->next = p -> next；

B.q ->next = p -> next；p -> next -> prior =q；p-> next=q；q->prior = p；

C.p-> next=q；q->prior = p；q ->next = p -> next；p -> next -> prior =q；

D.p -> next -> prior =q；q->prior = p；p-> next=q；q ->next = p -> next；

A.p -> prior = q；q-> next=p；p -> prior ->next=q； q ->prior= p -> prior；

B.q ->prior= p -> prior；p -> prior ->next=q；q-> next=p；p -> prior = q->next；

C.q-> next=p；p -> next=q；q-> prior ->next= q；q-> next=p；

D.p -> prior ->next=q；q-> next=p；q -> prior = p->prior；p -> prior = q；

A.P=60, Q=10

B.P=10, Q=6

C.P=40, Q=6

D.P=20, Q=20

A.*q++=*p;

B.q=p;

C.*q=*p;q++;

D.*p=*q;

E.*p=*q;p++;