题目
A.A cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n ),1))
B.B cfs <- 100 * (rep(couponRate/frequency, n-1) + c(rep(0, n - 1),1))
C.C cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1))
D.D cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1),1))
第1题
A.A cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n ),1))
B.B cfs <- 100 * (rep(couponRate/frequency, n-1) + c(rep(0, n - 1),1))
C.C cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1))
D.D cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1),1))
第2题
A.A cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n ),1))
B.B cfs <- 100 * (rep(couponRate/frequency, n-1) + c(rep(0, n - 1),1))
C.C cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1))
D.D cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1),1))
第3题
A.A cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n ),1))
B.B cfs <- 100 * (rep(couponRate/frequency, n-1) + c(rep(0, n - 1),1))
C.C cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1))
D.D cfs <- 100 * (rep(couponRate/frequency, n) + c(rep(0, n - 1),1))
第5题
第6题
第8题
A.随着时间的变化,双曲线贴现函数的递减趋势比指数函数更为陡峭
B.随着时间的延后,指数贴现函数的递减比例是递减的
C.双曲线贴现函数的时间偏好率是逐期递减的
D.双曲线贴现函数的解释力更强
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