30、()

A．VC—AC

B．VC—SIMI

C．PC—BIPAP

D．SPN—CPAP

A.point

B.similarity

C.difficulty

D.difference

t to point WAN links. Which of the masks below would you use？

A. /38

B. /30

C. /27

D. /23

E. /18

F. /32

有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point(int vx, int vy ) { x = vx; y = vy; } point () x = 0; y= 0; } point operator+(point p1 ) { point p; int px = x+ p1.x; int py = y + p1.y; return point(px, py ); point operator-(point p1 ) { point p; int px = x -p1.x; int py = y - p1.y; return point (px, py ); } void print() { cout＜＜x＜＜" , "＜＜y＜＜end1; }};int main (){ point p1(10, 10 ), p2(20, 20 ); p1 = p1 - p2; p1.print (); return 0;} 执行后的输出结果是

A．10，10

B．20，20

C．10，20

D．30，30

有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point(int vx, int vy ) { X=vx; y=vy; } point() { x=0; y=0; } point operator+ (point p1 ) { point p; int px = x + p1.x; int py = y+ p1.y; return point(px, py ); } point operator-(point p1 { point p; int px = x - p1.x; int py = y - p1.y; return point(px, py ); } void print() { cout＜＜x＜＜","＜＜y＜＜end1; }};int main(){ point p1(10, 10 ), p2(20, 20 ); p1 = p1 + p2; p1.print(); return ();}执行后的输出结果是()。

A．10, 10

B．20, 20

C．10, 20

D．30, 30

有如下程序： #include ＜iostream＞ using namespace std; class point { int x, y; public: point(int vx, int vy ) { x = vx; y = vy; } point () { x = 0; y = 0; } point operator+(point pl ) { point p; int px = x + p1.x; int py = y + p1.y; return point(px, py ); } point operator-(point p1 ) { point p; int px = x - p1.x; int py = y - p1.y; return point(px, py ); } void print() { cout＜＜x＜＜", "＜＜y＜＜end1; } }; int main () { point pl (10, 10 ), p2 (20, 20 ); p1 = p1 + p2; p1.print (); return 0; } 执行后的输出结果是()。

A．10,10

B．20,20

C．10,20

D．30,30

有如下程序： #include＜iostream＞ using namespace std； class point { int x，y； public： point(int vx，int vy) { x=vx； y=vy； } point() { x=0； y=0； } point operator+(point p1) { point p； int px=x+p1.x； int py=y+p1.y； return point(px，py)； } point operator-(point p1) { point p； int px=x-p1.x； int py=y-p1.y； return point(px，py)； } void print() { cout＜＜x＜＜","＜＜y＜＜end1； } }； int main() { point p1(10，10)，p2(20，20)； p1=p1+p2； p1.print()； retrun 0； } 执行后的输出结果是

A．10，10

B．20，20

C．10，20

D．30，30

A.3

B.30

C.300

D.3000

For this part, you are allowed 30 minutes to write an essay commenting on the saying “The decisions that people make quickly are always wrong.” You can give an example or two to illustrate your point of view. You should write at least 150 words but no more than 200 words.

请给出范文，谢谢！

ation explosion by referring to the saying "A wealth of information creates apoverty of attention. " You can give examples to illustrate your point and then explainwhat you can do to avoid being distracted by irrelevant information. You shouldwrite at least 150 words but no more than 200 words. ___________________________________________________________________________________________________________________________________________________________ ___________________________________________________________________________________________________________________________________________________________ ___________________________________________________________________________________________________________________________________________________________

A.荡秋千时，会荡秋千的人到最高点时站直，到最低点时蹲下，秋千会越荡越高； When playing on a Swing, the person who plays on a Swing will stand up straight at the highest point and squat down at the lowest point;#B.荡秋千时，会荡秋千的人到最高点时蹲下，到最低点时站直，秋千会越荡越高； When playing on a Swing, the person who plays on a Swing will crouch down at the highest point and stand up straight at the lowest point. The Swing will go higher and higher;#C.荡秋千时，不会荡秋千的人到最高点时站直，到最低点时蹲下，秋千会逐渐停止； In a Sw