题目
A.is helping
B.help
C.is going to help
D.helped
第1题
A.朝:为多音字,读“zhao”时意为早晨;读“chao”时,原意为朝拜,此引申为聚拢
B.长:为多音字,读“zhang”时同“涨”,意为涨潮;读“chang”时意为长时间、经常
C.上联读音为:yun ,zhao chao.zhao zhao chao ,zhao chao zhao san
D.下联读音为:chao ,chang zhang ,chang chang zhang ,chang zhang chang xiao
E.联语利用汉字谐音双关的特点,描绘了潮涨潮落、云聚云消的自然景象,显示了自然界变幻多姿的景色
第3题
A.Professor Zhang couldn’t be in the la
B.Professor Zhang forgot to turn off the lights in the laB
C.Professor Zhang went home a long time ago.
D.Professor Zhang was the last one to leave the la
B.
第4题
注意:请勿改动main()主方法和其他已有语句内容,仅在下划线处填入适当的语句。
程序运行结果如下:
fang
liu
ouyang
sun
wll
zhang
import java.util.*;
public class ex5_2{
public static void main(String[]args) {
Vector vName=new Vector();
String[]strName={"zhang","sun","wu","liu","fang","ouyang"};
for(int i=0;i<strName.length;i++){
________;
________;
}
for(int j=0;j<vName.size();i++){
System.out.println(vName.get(j));
}
}
}
第5题
阅读理解:根据上下文,补全对话内容。
A. Oh, amazing!
B. Yeah, right. Why?
C. Have you tried Yahoo?
D. you have lots of alternative search engines.
E. you can browse the Internet instead of going to the library.
MOLLY: Zhang, you are going to the library, right?
ZHANG HUA:{A; B; C; D; E}
MOLLY: Why not comfortably stay at home to log onto the Web?
ZHANG HUA: I need to look for some papers to add to my research report.
MOLLY: Well, {A; B; C; D; E}
ZHANG HUA: I tried Baidu for that, but didn't find the ones I need. I need some English papers, actually.
MOLLY: {A; B; C; D; E}
ZHANG HUA: Yahoo? No, but in my eyes, all search engines are quite similar.
MOLLY: You are right. But Baidu is good for Chinese searches, while Yahoo is better for searching data in English.
ZHANG HUA: {A; B; C; D; E} Never thought of that.4
MOLLY: That's too bad. In fact, {A; B; C; D; E}. Bing, AOL, Ask, Lycos, Sogou and even Yandex, to name a few.
第6题
A.第24行: strcmp(name, candidate[j].name) == 0 第26行: candidate[j].count++ 第34行: flag = 0 第41行: candidate[i].name, candidate[i].count
B.第24行: name == candidate[j].name 第26行: count++ 第34行: flag = 0 第41行: name, count
C.第24行: name = candidate[j].name 第26行: count++ 第34行: flag = 1 第41行: candidate[i].name[i], candidate[i].count
D.第24行: strcmp(name, candidate[j].name) == 0 第26行: candidate[j].count++ 第34行: flag = 1 第41行: name, count
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