题目
A)一般的科学家为了在社会上发展,都想尽快地申请科研项目。
B)总的说来,科学技术在各个领域的应用必将加速社会的发展。
C)大体上,对科学技术的应用都会使社会各个领域加速发展。
D)总之,科学家对科研项目的申请都是为了促进社会的发展。
E)总的说来,应用各个领域的科学技术都必将加速社会的发展。
第1题
第2题
We have only one vacancy, but so far have received more than 30 () for the job.
A、applications
B、applicants
C、applicators
D、appliances
第3题
We may infer from the second paragraph that
A.DNA technology has been widely applied to history research.
B.in its early days the U.S. was confronted with delicate situations.
C.historians deliberately made up some stories of Jefferson's life.
D.political compromises are easily found throughout the U.S. history.
第4题
A.different companies may have different requirements
B.dfferent companies may take different ttudes toward them
C.appli ants may be required to answer all the questions in detail
D.pi ants may have to send in the toms by person
第5题
The writer says the application form. is useful because it
A.reveals something of the applicant's character.
B.gives information about the applicant's family.
C.explains what skills the applicant has for the job.
D.shows how much the applicant wants to earn.
第6题
You use Microsoft .NET Framework 4 to create a Windows Presentation Foundation (WPF) application. The application has a window named MainWindow that has a StackPanel control named sp as the root element.You want to create a Button control that contains a TextBlock control with the "Save" Text property.You need to create the control dynamically and add the control to sp.Which code segment should you write in the constructor of the MainWindow class?()
A.
B.
C.
D.
第7题
阅读以下说明和Java代码,将应填入(n)处的字句写在对应栏内。
[说明]
编写一个字符界面的Java Application 程序,接受用户输入的10个整数,并输出这10个整数的最大值和最小值。
[Java 代码]
import java. io.* ;
public class abc
{
public static void main ((1))
{int i, n=10, max=0, min=0, temp=0;
try {
BufferedReader br = new BufferedReader (
new InputStreamReader (System.in ) );
max = min =Integer. parselnt (br. readLine () );
}. (2) (IOExccption e ) {} ;
for (i=2 ; i<=n ; i++ ) {
try {
BufferedReader br = new (3) (
new InputStreamReader (System. in ) );
temp =(4) (br. readLine ());
if (temp>max ) max=temp;
if (temp<min) (5)
} catch (IOException e ) {};
}
System.out.println ("max="+max+"\nmin="+min );
}
}
第9题
A.general
B.special
C.general and special
D.general or special
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