题目
第6题
【Java代码】 Abstract class Customer﹛ Protected String name; (1 )boolean isNil(); (2 )String getName(); ﹜ Class RealCustomer (3 )Customer{ Public RealCustomer(String name){ this.name=name; } Public String getName(){ return name ; } Public boolean is Nil() { return false; } ﹜ Class NullCustomer(4 )Customer﹛ Public String getName()﹛ return "Not Available in Customer Database"; ﹜ Public boolean isNil() ﹛ return true; ﹜ ﹜ class Customerfactory { public String[] names = {"Rob","Joe","Julie"}; public Customer getCustomer(String name) { for (int i = 0; i < names.length;i++) { if (names[i].(5 ))﹛ return new RealCustomer(name); ﹜ ﹜ return (6 ); ﹜ ﹜ Public class CrM﹛ Public viod get Customer()﹛ Customerfactory(7 ); Customer customer1-cf.getCustomer("Rob"); Customer customer2=cf.getCustomer("Bob"); Customer customer3= cf.getCustomer("Julie"); Customer customer4= cf.getCustomer("Laura"); System.out.println("customers”) System.out.println(customer1.getName()); System.out.println(customer2getName()); System.out.println(customer3.getName()); System.out.println(customer4.getName()); ﹜ Public static viod main (String[]arge)﹛ CRM crm =new CRM(); Crm.getCustomer(); ﹜ ﹜ /*程序输出为: Customers rob Not Available in Customer Database Julie Not Available in Customer Database */
第8题
联邦德国统一铁路改建和新建工程的报告系统分为()大类()小类。
A.4,120
B.5,120
C.4,125
D.5,125
第9题
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