题目
Except for the recession years of 1949, 1954, and 1958, the rate of economic growth exceeded the rate of productivity increase. However, in the late 1950s productivity and labor force were increasing more rapidly than usual, while the growth of output was slower than usual. This accounted for the change in employment rates.
But if part of the national purpose is to reduce and contain unemployment, arithmetic is not enough. We must know which of the basic factors we can control and which we wish to control. Unemployment would have risen more slowly or fallen more rapidly if productivity had in creased more slowly, or the labor force had increased more slowly, or the hours of work had fallen more steeply, or total output had grown more rapidly. These are not independent factors, however, and a change in any of them might have caused change in the other.
A society can choose to reduce the growth of productivity, and it can probably find ways to frustrate its own creativity. However, while a reduction in the growth of productivity at the expense of potential output might result in higher employment in the short run, the long-run effect on the national interest would be disastrous.
We must also give consideration to the fact that hidden beneath national averages is continuous movement into, out of, between, and within labor markets. For example, 15 years ago, the average number of persons in the labor force was 74 million, with about 70 million employed and 3.9 million unemployed. Yet 14 million experienced some term or unemployment in that year. Some were new entrants to the labor fore; others were laid off temporarily, the remainder were those who were permanently or indefinitely severed from their jobs. Thus, the average number unemployed during a year understates the actual volume of involunatary displacement that occurs.
High unemployment is not an inevitable result of the pace of technological change but the consequence of passive public policy. We can anticipate a moderate increase in the labor force accompained by a slow and irregular decline in hours or work. It follows that the output of the economy--and the aggregate demand to buy it--must grow by more than 4 percent a year just to prevent the unemployment rate from rising, and by even more if the unemployment rate is to fall further. Yet our
A.productivity rises at the same rate as growth of the labor force
B.productivity and labor force increase at a greater rate than output
C.output exceeds productivity
D.rate of economic growth is less than the number of man-hours required
第1题
A.Demand Index
B.Chaikin Money Flow.
C.Herrick Payoff Index.Your selection is incorrect
D.On Balance Volum
E.
第2题
在下面的运算符重载函数的原型中,错误的是()。
A.Volume operator-(double,dpible);
B.double Volume::operator-(double);
C.Volume Volume::operator-(Volume);
D.Volume operator-(Volume);
第3题
在下面的运算符重载函数的原型中,错误的是()。
A.Volume operator-(double,double);
B.double Volume::operator-(double);
C.Volume Volume::operator-(Volume);
D.Volume operator-(Volume,Volume);
第4题
阅读以下说明和C++程序,将应填入(n)处的字句写在对应栏内。
【说明】
以下程序的功能是计算正方体、球体和圆柱体的表面积和体积并输出。
程序由4个类组成:类cube、sphere和cylinder分别表示正方体、球体和圆柱体;抽象类 container为抽象类,提供了两个纯虚拟函数surface_area()和volum(),作为通用接口。
【C++程序】
include<iostream.h>
define pi 3.1416
class container{
protected:
double radius;
public:
container(double radius) {container::radius=radius;}
virtual double surface_area()=0;
virtual double velum()=0;
};
class cube:(1){ //定义正方体类
public:
cube(double radius):container(radius){};
double surface_area () {return 6 * radius * radius;}
double volum() {return radius * radius * radius;}
};
class sphere:(2){ //定义球体类
public:
sphere(double radius): container(radius){};
double surface_area() { return (3);}
double volum() {return pi * radius * radius * radius * 4/3;}
};
class cylinder:(4){ //定义圆柱体类
double height;
public:
cylinder(double radius,double height):container(radius)
{
container::height=height;
}
double surface_are a () { return 2 * pi * radius * (height+radius); }
double volum () {return (5);}
};
void main()
{
container * p;
cube obj1 (5);
sphere obj2(5);
cylinder obj3(5,5);
p=&obj1;
cout<<“正方体表面积”(<<p->surface_area()<<end1;
cont<<“正方体体积”<<p->volume()<<end1;
p=&obj2;
cout<<“球体表面积”<<p->surface_area()<<end1;
cout<<“球体体积”<<p->volume()<<end1;
p=&obj3;
cout<<“球体表面积”<<p->surface_area()<<end1;
cout<<“球体体积”<<p->volume()<<end1;
}
第5题
第6题
第10题
A.A.load setup defaults
B.B.save changes
C.C.discard changes
D.D.boot sequence
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