R1 is internal to area 1, and R2 is internal to area 2. Subnet 10.1.1.0/24 exists in area

x 2.2.2.0/24, with external metric 20. Router R22 redistributes an E2 route for the same prefix/length, external metric 10.Under what conditions will R1 choose as it s best route the route through R22？（）

A. R1 will always choose the route through R22.

B. As long as R1‘s best internal OSPF cost to reach R22 is less than 10.

C. As long as R1‘s best internal OSPF cost to reach R22 is less than 20.

D. R1 will never choo se the route through R22 if the E1 route through R2 is available.

1 and I2 used at th e ISPs. R1 peers with I1 and R2; R2 peers with I2 and R1. R1 and R2 do not share a common subnet, relying on other routers internal to the Enterprise for IP connectivity between the two routers.Which of the following could be used to prevent potential routing loops in this design？（）

A. Using an iBGP mesh inside the Enterprise core

B. Configuring default routes in the Enterprise pointing to both R1 and R2

C. Redistributing BGP routes into the Enterprise IGP

D. Tunneling the packets for the i BGP connection between R1 and R2

the following is true based on this output？（）R1 show ip bgp 19 0.1.0.0/16BGP routing table entry for 190.1.0.0/16, version 121Paths: (1 available, best 1, table Default - IP - Routing - Table)Advertised to update - groups:11 2 3 41.1.1.1 from 2.2.2.2 (3.3.3.3)Origin IGP, metric 0, localpref 100, valid, internal, best

A. R1 has a neighbor 1.1.1.1 command configured.

B. R1 has a neighbor 2.2.2.2 command configured.

C. The show ip bgp command lists a line for 190.1.0.0/16 with both an "＞" and an "i" on the left.

D. R1 is in ASN 1.

A. The LSA was created by an ABR due to an area range command.

B. The LSA was created by an ASBR due to a summary - address command.

C. If cr eated by an area range command, the best metric for a subordinate subnet on that ABR must have been 11.

D. None of the other answers is correct.

从基本的CPU工作原理来看，若CPU执行MOV R1，R0指令(即将寄存器R0的内容传送到寄存器R1中)，则CPU首先要完成的操作是(62)。(其中PC为程序计数器，M为主存储器，DR为数据寄存器，IR为指令寄存器，AR为地址寄存器。)

A．R0→R1

B．PC→AR

C．M→DR

D．DR→IR

connected to area 1 are performing Type 3 LSA filterinG. Which of the following answers is true based on the information in the output from B1？（）R1 show ip route 10.1.0.0 255.255.0.0 longer - prefixes! Legend lines omitted for brevity10.0.0.0/8 is variably subnetted, 17 subnets, 3 masksO 10.1.2.0/24 [110/658] via 10.10.13.1, 00:00:32, Serial0/0/0.1O IA 10.1.1.0/24 [110/658] via 10.10.23.2, 00:41:39, Ser ial0/0/0.2O IA 10.1.3.0/24 [110/658] via 10.10.23.2, 00:41:39, Serial0/0/0.2

A. A Type 3 LSA for 10.2.2.0/24 was filtered by both ABRs

B. A Type 3 LSA for 10.1.2.0/24 was not filtered by both ABRs

C. A Type 3 LSA for 10.1.3.0/24 was not filtered by at least one ABR

D. A Type 3 LSA for 10.1.1.0/24 filtered by both ABRs

内环境(internal environment)