题目
A.a[-3]
B.a[2:13]
C.a[::3]
D.a[x]
第3题
A.1
B.50
C.100
D.10000
第4题
A.def product1(num): product=1 for i in range(1,num+1): product=product *i return product print(product1(10))
B.def sum1(num): sum2=0 for i in range(1,num+1): sum2+=i return sum2 print(sum1(100))
C.def product2(num): if num==1: return 1 else: return num *product2(num-1) print(product2(10))
D.def sum_a(num1): if num1==1: return 1 else: return num1+sum_a(num1-1) print(sum_a(100))
第5题
A.def product1(num): product=1 for i in range(1,num+1): product=product *i return product print(product1(10))
B.def sum1(num): sum2=0 for i in range(1,num+1): sum2+=i return sum2 print(sum1(100))
C.def product2(num): if num==1: return 1 else: return num *product2(num-1) print(product2(10))
D.def sum_a(num1): if num1==1: return 1 else: return num1+sum_a(num1-1) print(sum_a(100))
第6题
A.def product1(num): product=1 for i in range(1,num+1): product=product *i return product print(product1(10))
B.def sum1(num): sum2=0 for i in range(1,num+1): sum2+=i return sum2 print(sum1(100))
C.def product2(num): if num==1: return 1 else: return num *product2(num-1) print(product2(10))
D.def sum_a(num1): if num1==1: return 1 else: return num1+sum_a(num1-1) print(sum_a(100))
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