If the genome size is small, then sequencing of the entire genome is ___________

A.1/10

B.1/8

C.1/6

D.1/5

A.I want size 26.

B.We got various sizes.

C.This size is not for m

D.We want a small siz

n I do for you？ C．How about this one？ D．What size does your father wear？

A.What size do you wear?

B.What can I do for you?

C.How about this one?

D.What size does your father wear?

public: Stack(unsigned n=10:size(n){rep_=new int[size];top=O;} Stack(Stack&s):size(s.size) { rep_=new int[size]; for(int i=0;i＜size;i++)rep_[i]=s.rep_[i]; top=s.top; } ～Stack(){delete[]rep_;} void push(int a){rep_[top]=a; top++;} int opo(){--top;return rep_[top];} bool is Empty()const{return top==O;} pavate: int*rep_; unsigned size,top; }; int main() { Stack s1; for(int i=1;i＜5;i++) s1.push(i); Stack s2(s1); for(i=1;i＜3;i++) cout＜＜s2.pop()＜＜','; s2.push(6); s1.push(7); while(!s2.isEmpty()) cout＜＜s2.pop()＜＜','; return 0； } 执行上面程序的输出是

A．4，3，2，1

B．4，3，6，7，2，1

C．4，3，6，2，1

D．1，2，3，4

下面程序的运行结果是#include #define SIZE 12sub(char *a，int t1，int t2) { char ch； while(t1＜t2) { ch=*(a+t1)； *(a+t1)=*(a+t2)； *(a+t2)=ch； t1++；t2--； }} main() { char s[SIZE]={’A’,’B’,’C’,’D’,’E’,’F’,’G’,’H’,’I’,’J’,’K’,’L’}； int i； sub(s，7，SIZE-1)； for(i=0；i＜SIZE；i++) printf("%c "，s[i])； printf("\n")；}

A.sum up

B.size up

C.figure out

D.wipe out

A.What size do you wear？

B.What can I do for you？

C.How about this one？

D.Whatsize does your father wear？

Customer: The jeans look cool. May I try them on？ Salesman: Sure.______

A．What size, please？

B．It's 34 RMB, please.

C．Help yourself, please.

D．Cash or charge？